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Say the horizontal distance is 100 feet, launch height about 7 feet (not sure how tall exactly he is), final height of the rim is 10 feet, launch angle is 45 degrees and gravity is 9.81 m/s2.
We can the find that the initial velocity is 17.58 m/s.
Based on the initial velocity, the ball's maximum height in this trajectory is approximately 9.96 meters.
Since the launch and landing points are close in height, we can say that the maximum height above the chord is 7.83 meters.
We can then use all for his to compute the arc length at 31.08 meters (101.97 feet).
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Say the horizontal distance is 100 feet, launch height about 7 feet (not sure how tall exactly he is), final height of the rim is 10 feet, launch angle is 45 degrees and gravity is 9.81 m/s2.
We can the find that the initial velocity is 17.58 m/s.
Based on the initial velocity, the ball's maximum height in this trajectory is approximately 9.96 meters.
Since the launch and landing points are close in height, we can say that the maximum height above the chord is 7.83 meters.
We can then use all for his to compute the arc length at 31.08 meters (101.97 feet).
Hope I didn’t miss anything.
He’s 6’2 and it came out of his hand just above his shoulder, so I’d put the launch height estimated at 68”
Long arm